16x^2-48x-28=0

Solution for 16x^2-48x-28=0 equation:

16x^2-48x-28=0

a = 16; b = -48; c = -28;
Δ = b2-4ac
Δ = -482-4·16·(-28)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-64}{2*16}=\frac{-16}{32}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+64}{2*16}=\frac{112}{32}
=3+1/2
$